Sample Problems:
Problem: ABCD is a parallelogram and FBED is a square. What is the perimeter of ABCD if BD (not shown) equals 8√2 and AB = 10?
Solution: Since FBED is a square, BF = FD and Triangle BFD is a 45-45-90 triangle.
Since Triangle BFD is a 45-45-90 triangle, s = 8. Then AF can be found with the Pythagorean Theorem.
a2 + b2 = c2 --> a2 + 82 = 102 --> a2 = 36 --> a = 6 --> AF = 6
Perimeter = AB + BC + CD + DA = 10 + 14 +10 + 14 = 48
Problem: A 6 sided regular polygon (hexagon) is inscribed in a circle of radius 10 cm, find the length of one side of the hexagon.
Solution:
- Angle AOB is given by
angle (AOB) = 360o / 6 = 60o - Since OA = OB = 10 cm, triangle OAB is isosceles which gives
angle (OAB) = angle (OBA) - So all three angles of the triangle are equal and therefore it is an equilateral triangle. Hence
AB = OA = OB = 10 cm.